Math, asked by 12tamanna, 11 months ago

during every financial year, the value of a machine depreciates by 12%. find the original cost of a machine which depreciates by 2640 rupees during tge second financial year of its purchase.​

Answers

Answered by amanraj56
0

Answer:

given,

rate of decreasing=12%

decreased money=2640

time=2 year

a/q

decreased money=p- p(1-r/100)^n

2640=p -p(1-12/100)²

2640=p -p(88/100)²

2640=p-p(22/25)²

2640=p-p(484/625)

2640=484p/625

2640=141p/625

2640×625=141p

1650000=141p

1650000/141=p

11702.12766=p

answer will be 125000 if it is decreases. by 5640

5640=484p/625

5640=141p/625

5640×625=141p

3525000 =141p

3525000/141=p

125000=p

check the answer correct me if I wrong


12tamanna: its all wrong
12tamanna: correct answer is 25000 rupees but i don't know the process how to do it man..
amanraj56: may be i m right
12tamanna: maybe who knows
amanraj56: answer must be 25000 if it decreases by 5640 not by2650 so I recommend u to check the question
amanraj56: not by2640
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