Question

During one year the population of town increases 10% and the next year decreased by 10% .the population at the end of the second year was 20295. what was it in the begging in the first year

Answer 1

Let the population of town is 10
First year it will be 10% more = 110
Again next year it was reduced by 10% = 110-(110 x 10/100) = 110-11 = 99
Therefore 99 is equal to 20295
Then 100 is equal to (20295/99) x 100
= 205 x 100
= 20500
Therefore, the population in the beginning
= 20500

Answer 2

Answer:

20500

Step-by-step explanation:

Let the population of town is 10

First year it will be 10% more = 110

Again next year it was reduced by 10% = 110-(110 x 10/100) = 110-11 = 99

Therefore 99 is equal to 20295

Then 100 is equal to (20295/99) x 100

= 205 x 100

= 20500

Therefore, the population in the beginning

= 20500