Physics, asked by SRINIJA123, 4 months ago

During the execution of a play, a football player carries the ball for a distance of 33 m in the direction 58° north of east. To determine the number of meters gained on the play, find the eastward component of the ball’s displacement.

Answers

Answered by krish78619
1

Explanation:

Given

Direction is North of east i.e. 58° with x axis

Also ball moved by 33 m

therefore its east component is 33cos58=17.48 m

Northward component

= 33sin 58 = 27.98 m

= 28 m.

Answered by Sanav1106
0

The eastward displacement of the component will be 18m.

The northward displacement of the component will be 28m.

GIVEN: A football player carries the ball for a distance of 33 m in the direction 58° north of east.
TO FIND The eastward component of the ball’s displacement.
SOLUTION:

As we are given in the question,

A football player carries the ball for a distance of 33 m in the direction 58° north of east.

According to the question,

Distance covered = 33m

Direction = 58° north of east.

Implying that,
Direction is North of east i.e. 58° with the x-axis

Therefore,

The east component of the ball particle is

= 33cos58

= 17.48 m

= 18 m

Similarly,

Northward component of ball particle,

= 33sin 58

= 27.98 m

= 28 m.

Therefore,

The eastward displacement of the component will be 18m.

The northward displacement of the component will be 28m.

#SPJ2

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