During the execution of a play, a football player carries the ball for a distance of 33 m in the direction 58° north of east. To determine the number of meters gained on the play, find the eastward component of the ball’s displacement.
Answers
Explanation:
Given
Direction is North of east i.e. 58° with x axis
Also ball moved by 33 m
therefore its east component is 33cos58=17.48 m
Northward component
= 33sin 58 = 27.98 m
= 28 m.
The eastward displacement of the component will be 18m.
The northward displacement of the component will be 28m.
GIVEN: A football player carries the ball for a distance of 33 m in the direction 58° north of east.
TO FIND The eastward component of the ball’s displacement.
SOLUTION:
As we are given in the question,
A football player carries the ball for a distance of 33 m in the direction 58° north of east.
According to the question,
Distance covered = 33m
Direction = 58° north of east.
Implying that,
Direction is North of east i.e. 58° with the x-axis
Therefore,
The east component of the ball particle is
= 33cos58
= 17.48 m
= 18 m
Similarly,
Northward component of ball particle,
= 33sin 58
= 27.98 m
= 28 m.
Therefore,
The eastward displacement of the component will be 18m.
The northward displacement of the component will be 28m.
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