Question

A 5.0 cm long object is placed at a distance of 20 cm from
a convex lens of focal length 10 cm. Object is placed normal
to the principal axis of the lens. Find out nature, position
and size of the image. Solve the sums Please​

Answer 1

Explanation:

h₀=5 cm

u= -20 cm

f= 10 cm

By lens formula;

$\frac{1}{v} - \frac{1}{u} =\frac{1}{f}$

$\frac{1}{v} =\frac{1}{10}-\frac{1}{20}$

or  $\frac{1}{v} = \frac{2-1}{20}$

or  $\frac{1}{v} =\frac{1}{20}$

or  $v=20$ cm

Now as v is positive so,

The image is real and inverted.

As the object is at the 2F' so the image will be formed at 2F i.e. other side of the lens.

We know,  $\frac{v}{u}=\frac{hi}{ho}$

$\frac{20}{-20}=\frac{hi}{5}$

or  $hi=-5cm$

Size of the image= -5 cm

Please mark as the brainliest  ...

It took a lot of time for me ...