Question

During the first 18 min of a 60 min trip, a car has an average speed of 14m/s. What should be the average speed for remaining 42 min so that car is having an average speed of 21 m/s for the entire journey?

Answer 1

Answer:

↔️Distance covered in first 18 min = 11×18×60=11880m

Let average speed for remaining trip be 'v'.

Thus distance covered in remaining time = v×42×60=2520vm

Thus total distance, D=11880+2520v

total time, T=60min=3600sec

Thus Avg.Speed=21=TD(11880+2520v)=21×3600v≈25.3m/↩s↩

Explanation:

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Answer 2

Answer:Distance covered in first 18 min = 11×18×60=11880m

Let average speed for remaining trip be 'v'.

Thus distance covered in remaining time = v×42×60=2520vm

Thus total distance, D=11880+2520v

total time, T=60min=3600sec

Thus Avg.Speed=21= D/T

(11880+2520v)=21×3600

v≈25.3m/s

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