Math, asked by zhiya78, 2 months ago

During the month of June, 2020, EJAY to and JDT Merchandise entered into the

following transactions:

June 5 Ejay purchased merchandise on account from JDT, P243,000. Terms:

FOB shipping point; 3/10, n/30. Paid freight charges amounts to P4,000

June 7 Ejay purchased merchandise on account from JDT, P470,000. Terms:

FOB destination; 3/10, n/30. Freight charges amounted to P7,000

June 8 Ejay returned P18,000 of merchandise to JDT from June 5 purchase

June 10 Ejay paid JDT the amount due on the June 5 transaction

June 11 JDT paid the transportation charges on the June 7 shipment

June 14 Ejay paid JDT the amount due from the June 7 shipment

June 21 Ejay purchased merchandise from JDT on account, P270,000. Terms:

20% trade discount; FOB shipping point; 3/10, n/30

June 25 Freight charges on the June 21 transaction amounted to P3,000 and were

paid by Ejay.

June 26 Ejay paid JDT the amount due on the June 21 transaction.

Required:

1. Prepare the journal entries for Ejay Store.

2. Prepare the journal entries for JDT Merchandise.​

Answers

Answered by gargivy1510
1

Answer:

Given:-

Rear view mirror i.e it is a convex mirror

Radius of curvature ( C ) = 3 m

object distance ( u ) = -5 m

To find:-

image distance ( v )

nature of image

size of image

Formula:-

\implies⟹ \underline{\boxed{\sf \dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}}}

f

1

=

v

1

+

u

1

\implies⟹ \underline{\boxed{\sf m = \dfrac{-v}{u}}}

m=

u

−v

Solution:-

\implies⟹ \sf\dfrac{1}{3}

3

1

= \sf\dfrac{1}{v}

v

1

+ \sf\dfrac{1}{-5}

−5

1

\implies⟹ \sf\dfrac{1}{v}

v

1

= \sf\dfrac{1}{3}

3

1

+ \sf\dfrac{1}{5}

5

1

\implies⟹ \sf\dfrac{1}{v}

v

1

= \sf\dfrac{3+5}{15}

15

3+5

\implies⟹ \sf\dfrac{1}{v}

v

1

= \sf\dfrac{8}{15}

15

8

\implies⟹ \sf vv = \sf 1.251.25

Nature:- The positive sign of this image shows that it is Virtual and erect image.

Size of this image

\implies⟹ m = \sf\dfrac{-1.25}{-5}

−5

−1.25

\implies⟹ m = 0.25

hence, this image is smaller than the object

_________________________

Additional information:-

Cases in Concave mirror -

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{cccc}\sf \pink{Position_{\:(object)}} &\sf \purple{Position_{\:(image)}} &\sf \red{Size_{\:(image)}} &\sf \blue{Nature_{\:(image)}}\\\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad\qquad}{}&\frac{\qquad \qquad \qquad \qquad\qquad}{}\\\sf At \:Infinity &\sf At\: F&\sf Highly\:Diminished&\sf Real\:and\:Inverted\\\\\sf Beyond\:C &\sf Between\:F\:and\:C&\sf Diminished&\sf Real\:and\:Inverted\\\\\sf At\:C &\sf At\:C&\sf Same\:Size&\sf Real\:and\:Inverted\\\\\sf Between\:C\:and\:F&\sf Beyond\:C&\sf Enlarged&\sf Real\:and\;Inverted\\\\\sf At\:F&\sf At\:Infinity&\sf Highly\: Enlarged&\sf Real\:and\:Inverted\\\\\sf Between\:F\:and\:P&\sf \: Behind\:the\:mirror&\sf Enlarged&\sf \: Erect\:and\:Virtual\end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

Position

(object)

AtInfinity

BeyondC

AtC

BetweenCandF

AtF

BetweenFandP

Position

(image)

AtF

BetweenFandC

AtC

BeyondC

AtInfinity

Behindthemirror

Size

(image)

HighlyDiminished

Diminished

SameSize

Enlarged

HighlyEnlarged

Enlarged

Nature

(image)

RealandInverted

RealandInverted

RealandInverted

RealandInverted

RealandInverted

ErectandVirtual

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