Question

Duscriminant of equation (X+5)(X+5)=2

Answer 1

Answer:

$\large\bold\red{8}$

Step-by-step explanation:

Given,

$(x + 5)(x + 5) = 2 \\ \\ = > {(x + 5)}^{2} - 2 = 0 \\ \\ = > {x}^{2} + 2 \times 5 \times x + {5}^{2} - 2 = 0 \\ \\ = > {x}^{2} + 10x + 25 - 2 = 0 \\ \\ = > {x}^{2} + 10x + 23 = 0$

Clearly, it is a quadratic equation in variable x.

where,

a = 1

b = 10

c = 23

Now,

we know that,

Descriminant , D of a quadratic equation is given by,

$D = {b}^{2} - 4ac$

Therefore,

putting the values,

we get,

$= > D = {(10)}^{2} - 4 \times 1 \times 23 \\ \\ = > D = 100 - 92 \\ \\ = > D = 8$

Hence,

Descriminant = 8