Question

dvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

Answer 1

Answer:

okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

Answer 2

${\huge{\star}{\color{skyblue}{\rm{Given \: statement}}}} \huge\star \\ \\ Balls \: in \: bag \: 1:- \\ Red \: = \: 3 \\ Blue \: = \: 7 \\ \\ \\ Total \: balls \: in \: bag \: 2 \: = \: 40 \\ \\ Let \: probability \: of \: drawing \: blue \: ball \\ \: from \: bag \: 2 =x \\ \\ \\ \\ \large{\huge{\underline \mathbb{ \overline { \mid{ \blue{Answer✍} \mid}}}} }$

$\: Probability \: of \: blue \: ball \\ \: from \: bag \: 1 \: = \frac{4x}{3}$

$Probability \: of \: blue \: ball \: \\ in \: bag \: 1 = \frac{possible \: outcome}{total \: outcome} \\ \\ \frac{7}{10} = \frac{4x}{3} \\ \\ 21 = 40x \\ \frac{21}{40} = x$

$So \: the \: probability \: of \: Blue \: ball \\ \: from \: bag \: 2 \: = \frac{possible \: outcome}{total \: outcome } \\ \\ \frac{21}{40} = \frac{possible \: outcome}{40} \\ \\ \frac{21 \times \cancel{40}}{ \cancel{40}} = possible \: outcome \\ \\ 21= possible \: outcome$

So no. of blue balls in bag 2 is 21