Question

∫dx/√(9-25x²) = ?

(a) sin⁻¹(5x/3) + c
(b)1/5 sin⁻¹ (5x/3) + c
(c) 1/6 log (3+5x)/(3-5x) + c
(d) 1/30 log (3+5x)/(3-5x) + c

Answer 1

Explanation:

dx/√(9-25x²) = ?

(a) sin⁻¹(5x/3) + c

(b)1/5 sin⁻¹ (5x/3) + c

(c) 1/6 log (3+5x)/(3-5x) + c ✓✓✓✓

(d) 1/30 log (3+5x)/(3-5x) + c

Answer 2

Answer:

I think option is right....

(c) 1/6 log (3+5x)/(3-5x) + c

@Hopeless