Question

dy/dx
= 4x + y + 1, suitable
For solving
substitution is
y= vx
y = 4x
y= 4x+v
y + 4x+ 1 = v​

Answer 1

Answer:

Last answer y + 4x+ 1 = v

Step-by-step explanation:

y + 4x+ 1 = v

dy/dx+4=dv/dx

dy/dx=dv/dx-4=v

dv/dx=v+4

integrated both side

ln(v+4)=x +c

Put v

ln(y + 4x+ 1) =x+c