dy/dx of 1/x i want this answer urgently from any one
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-1/x square is the answer
SHAHILKHAN:
correct
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Differentiate both sides of the equation.
ddx(y)=ddx(1x)ddx(y)=ddx(1x)
The derivative of yy with respect to xx is y'y′.
y'y′
Differentiate the right side of the equation
−1x2-1x2
Reform the equation by setting the left side equal to the right side.
y'=−1x2y′=-1x2
Replace y'y′ with dydxdydx.
dydx=−1x2
ddx(y)=ddx(1x)ddx(y)=ddx(1x)
The derivative of yy with respect to xx is y'y′.
y'y′
Differentiate the right side of the equation
−1x2-1x2
Reform the equation by setting the left side equal to the right side.
y'=−1x2y′=-1x2
Replace y'y′ with dydxdydx.
dydx=−1x2
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