E and F are points on the side PQ and PR respectively of ∆PQR. If PE=4cm, QE=4.5cm, PF=8cm and RF=9, state whether EF||QR
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PE = 4 cm, QE = 4.5 cm, PF = 8cm, RF = 9cm
∴ PE/QE = 4/4.5 = 40/45 = 8/9 [By using Basic proportionality theorem]
And, PF/RF = 8/9
So, PE/QE = PF/RF
Hence, EF is parallel to QR.
Step-by-step explanation:
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