E and F are respectively the mid point of equal sides AB and AC of Δ ABC (see figure) then
(A) BF = AC
(B) BE = AF
(C) CE = AB
(D) BF = AC
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MATHS
E and F are respectively the mid-point of equal sides AB and AC of △ABC
Show that BF=CE
ANSWER
Given E and F are mid point of equal sides AB and AC of triangle ABC
In ΔABF and ΔACE
AB=AC (given )
∠A=∠A (common angle )
AF=AE (halves of equal sides)
∴ΔABF≅ΔACE (SAS rule)
∴BF=CF (CPCT)
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