E and for are respectively the midpoint of equal side AB and AC of ABC show that BF=CE
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Since AB=AC
ALSO E IS THE M.P OF AC
SO 1/2AC=BE........1
AND F IS THE M.P OF AB
SO BF=1/2AB........2
FROM 1 AND 2 WE GET
BF =BE , AS AB=AC
HENCE PROVE
ALSO E IS THE M.P OF AC
SO 1/2AC=BE........1
AND F IS THE M.P OF AB
SO BF=1/2AB........2
FROM 1 AND 2 WE GET
BF =BE , AS AB=AC
HENCE PROVE
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