Question

E. chlorine + sulphur dioxide + water → sulphuric acid + hydrogen chloride balance it.

Answer 1

Balanced equation for reaction between chlorine, Sulphur and water

The given word equation for the reaction is:

Chlorine + Sulphur dioxide + Water \rightarrow Sulfuric acid + Hydrogen chloride.

When the chemical equation for the above reaction is written it gives:

Cl_2+SO_2+H_2O\rightarrow H_2SO_4+HCl

For the above equation when the number of atoms for the reactant side is calculated it gives:

Cl = 2

S = 1

H = 2

O = 3

Explanation:

Answer 2

Answer:

$Cl_{2} + SO_{2} + H_{2}O --> H_{2}SO_{4} + HCl$

LHS

Cl - 2

S - 1

O - 3

H - 2

RHS

Cl - 1

S - 1

O - 4

H - 3

$Cl_{2} + SO_{2} + 2H_{2}O --> H_{2}SO_{4} + HCl (equalising O)\\Cl_{2} + SO_{2} + 2H_{2}O --> H_{2}SO_{4} + 2HCl (equalising H)\\Cl_{2} + SO_{2} + 2H_{2}O --> H_{2}SO_{4} + 2HCl$

LHS

Cl - 2

S - 1

O - 4

H - 4

RHS

Cl - 2

S - 1

O - 4

H - 4

Balanced.