Question

e. coli chromosome contains 4,639,221 bp. (a) how many turns of the double helix must be unwound during replication of the

e. coli chromosome?

Answer 1

one Turn of Double stranded chromosome contains 10 Base pairs.

For 46,39,221 base pairs , total number of Turns of DNA are 463922.1.

therefore , total 4,63,922 turns must be unwound during DNA replication.

Answer 2

Answer:

Chromosomes are considered as the tread like bodies present in the nucleus of all the living plants and animals. Chromosome contains protein and DNA.

Explanation:

We have been given the total bp of e coli chromosome.

We have to find out the total turns of the double helix required to unbound during the replication of the e coli chromosome.

Final answer:

1 turn of e coli chromosome contains 10 bp.

Therefore, for 46,39,221 bp,

Total number of Turns of DNA = 463922.1.

Total 4,63,922 turns must be unwound during DNA replication.

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