Question

E.Coli ribonuclease contains 124 amino acids .The number of nucleotide present in the gene encoding the protein is

Answer 1

the number of nucleotide is 31

Answer 2

Answer: the correct answer is 375

Explanation:

1 amino acid is coded by 3 nucleotides.

So, 124 amino acids will be coded by (124×3)= 372 nucleotides.

There are 3 stop codons.

So, the total number of nucleotides present to code for that gene is 372+3= 375nucleotides