e) Find the greatest number that will divide 93, 111 and 129 leaving remainder 3 in each case.
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6
Answer:
Step-by-step explanation:
Since Remainder is 3 in each case numbers are 93 – 3 = 90 111 – 3 = 108 129 – 3 = 126 Required number will be HCF of 90,108 and 126 HCF of 90 and 108 So. Greatest number will be =18
Answered by
1
Answer:
18
Step-by-step explanation:
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