Question

e) In SHM, acceleration of a particle at its mean position is
(i) zero (ii) maximum
(iii) minimum (iv) between maximum and minimum​

Answer 1

Answer:

Option 1.

See below.

Explanation:

The acceleration of an object executing Simple Harmonic motion is given by,

$a=-\omega ^{2}x$

At the mean position, x = 0, therefore the acceleration is zero.

See the image,

At the equilibrium position,

$\sin \theta =0\Leftrightarrow g\sin \theta =0$