Question

А
E
In the adjoining figure, ZABC = ZACB, D and E are
points on the sides AC and AB respectively such that
BE = CD. Prove that
(1) AEBC = ADCB
(in) AOEB = AODC
(it) OB = OC
B​

Answer 1

Step-by-step explanation: In the given figure if A ABC - A ADE, AD = 12, AE = 9, AB = 18, DE = 5, then find AC and BC.​

Step-by-step explanation: OR in AABC, D and E are points on the sides AB and AC respectively, such that DE || BC. If AD = x, DB = x -2, AE = x + 2 and EC = X -1, Find the value of x.​

In a ΔABC, D and E are points on sides AB and AC respectively such that DE || BC. If AD = X, DB = x-2, AE = X + 2 and EC = x- 1 then x is equal to ?​

1) In figure BC 1 AB, AD 1 AB, BC = 4, AD = 8 then find, A(AABC) A(AADB) ​

4. In the adjoining figure, ZABC = ZDCB = 90°, AB = 6, DC = 8, then A(AABC) = 2 [1 Mark] A (ADCB)​