E is the mid point of side BC if DE and AB when produced meet at point F. Prove that AF=2AB
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Step-by-step explanation:
EC=EB GIVEN
Angle DEC=BEF vertically opposite angles
angle DCB=EBF alternate interior angles are equal
therefore triangles are congruent
from which we get Dc=BF
DC=AB
Therefore AB=BF
AB+BF=AF
therefore AF=2BF
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