Question

e molar conductivity of 0.01M KCl Solution is 152 S cm^2 mol^-1 then then the conductivity of the solution​

Answer 1

Given:

Molar conductivity = 152 Scm⁻²mol⁻¹

Concentration = 0.01M

To find:

Conductivity of solution.

Solution:

Lets first define the conductivity of the solution, it is the measure to determine the ability of a solution to conduct electricity.

It's SI unit is Siemens per centimeter.

Formula used to determine conductivity is as follows-

          $\Lambda _m = \frac{\kappa \times 1000}{c}$

or,      $\kappa = \frac{\Lambda _m \times c}{1000}$

here, κ = conductivity

         $\Lambda _m$ = molar conductivity = 152 Scm⁻²mol⁻¹

         c = concentration = 0.01M

therefore, substituting all the values we get,

        $\kappa = \frac{152 \times 0.01}{1000}$

       $\kappa = \frac{1.52}{1000}$

       κ = 0.00152 Scm⁻¹.

Therefore, the conductivity of the solution is found to be 0.00152 Scm⁻¹.