Question

E. Numerical questions
1. On a cold winter day, the temperature was 23 °cWhat would this temperature be in degree
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Answer 1

Answer:

Explanation:

he change in length is given as,

ΔL=LαΔT

L

ΔL

​  

=11×10  

−6

×30

The error percentage is given as,

%e=(  

L

ΔL

​  

×100)%

%e=(11×10  

−6

×30×100)%

=3.3×10  

−2

%

(b)

The change in length is given as,

ΔL=LαΔT

L

ΔL

​  

=11×10  

−6

×10

The error percentage is given as,

%e=(  

L

ΔL

​  

×100)%

%e=(11×10  

−6

×10×100)%

=1.1×10  

−2

%

Thus, the error percentages are 3.3×10  

−2

% and 1.1×10  

−2

%