Question

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(b)) In the figure (ii) given below, AB and CD are equal chords of a we w
O. IF AB and CD meet at E (outside the circle) prove that

(ii) BE = DE​

Answer 1

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Your answer is here $.$

=> Given : AB & CD is a equal chord Construction: Meet O line to E and
O is perpendicular to D and
O is """"""""""""""''''''''''''' B.

To prove : BE = DE

Proof => In ∆ EDO and ∆ EBO
$L$1 = $L$2 (each 90°)
OE = OE (Common )
OD = OB (radii of same circle )

∆ EDO 〰 ∆ EBO (R.H.S)
DE = BE (C.P.C.T)

$hence \: \: proved$

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