Question

(e) The length of a rectangle exceeds its breadth by 9cm. If the length and the
breadth are each increased by 3 cm, the area of the new rectangle forms
will be 84cm´ more than that of the given rectangle. Find the length and
breadth of the given rectangle.
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Answer 1

Answer:

length= 17 cm and breadth=8cm

Step-by-step explanation:

let the breadth of rectangle be X and length be X+ 9 cm.

area of rectangle = length ×breadth

= X ×( X +9)

=X sq. + 9X.....(i)

breadth of new rectangle =X+ 3 cm

length of new rectangle=X+9+3=X+12 cm

A/Q,

=> (X+3) ×(X+12)= X sq. +9X+ 84

=> X sq. + 12X+ 3X+ 36= X sq. +9X +84

=> X sq. - X sq. + 12X + 3X- 9X= 84-36

=> 6X =48.

=> X= 48/ 6

=> X= 8

Therefore, length=X+ 9= 8+9=17 cm

& breadth=X= 8cm.