E value evaluate using identity 105 X 102
Answers
Answered by
49
105 × 102
= (100+5)(100+2)
= 10000 + 200 + 500 + 10
= 10710
= (100+5)(100+2)
= 10000 + 200 + 500 + 10
= 10710
Answered by
32
Hi there !!
Given,
to evaluate using algebraic identity,
the product of 105 × 102
105 can be written as 100 + 5
102 can be written as 100 + 2
so,
105 × 102 = (100 + 5)(100 + 2)
the following product (100 + 5)(100 + 2) is in the form of identity (x + a)(x + b) = x² + x(a + b) + ab
Substituting the values,
we have,
(100)² + 100(5 + 2) + 5×2
= 10000 + 700 + 10
= 10710
Thus, 105 × 102 is 10710
Given,
to evaluate using algebraic identity,
the product of 105 × 102
105 can be written as 100 + 5
102 can be written as 100 + 2
so,
105 × 102 = (100 + 5)(100 + 2)
the following product (100 + 5)(100 + 2) is in the form of identity (x + a)(x + b) = x² + x(a + b) + ab
Substituting the values,
we have,
(100)² + 100(5 + 2) + 5×2
= 10000 + 700 + 10
= 10710
Thus, 105 × 102 is 10710
Anonymous:
:-)
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