Math, asked by mithleshgaur12p61dp9, 1 year ago

E value evaluate using identity 105 X 102

Answers

Answered by Anonymous
49
105 × 102
= (100+5)(100+2)
= 10000 + 200 + 500 + 10
= 10710
Answered by Anonymous
32
Hi there !!

Given,
to evaluate using algebraic identity,
the product of 105 × 102

105 can be written as 100 + 5
102 can be written as 100 + 2

so,

105 × 102 = (100 + 5)(100 + 2)

the following product (100 + 5)(100 + 2) is in the form of identity (x + a)(x + b) = x² + x(a + b) + ab

Substituting the values,
we have,

(100)² + 100(5 + 2) + 5×2

= 10000 + 700 + 10

= 10710

Thus, 105 × 102 is 10710

Anonymous: :-)
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