(e) Value of the following:
(i)[72-12 = 3 of 2] + (18 - 6) = 4.
(ii)7+(8 - 3 of 2)
QUESTION6)Solve the following(write statements)
(a)Find the smallest number which leaves remainders 8 and 12 when divided by
28 and 32 respectively.
3
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1) [72 - 12 = 3 of 2] + 12 = 4
• [60 = 3 × 2] = 4 - 12
• [ 60 = 6 ] = -8
• 60 = 6 = -8
• 60 = -8-6
• 60 = -14
• -14-60
• -74
2) 7 + (5 of 2)
• 7 + 10
• 17
3) Given that the smallest number when divided by 28 and 32 leaves remainder 8 and 12 respectively. 28 - 8 = 20 and 32 - 12 = 20 are divisible by the required numbers. Therefore the required number will be 20 less than the LCM of 28 and 32. = 224.
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