Science, asked by kishorbairagi, 10 months ago

e^x=243 and e^y=32 then e^(3x+4x)/5=?​

Answers

Answered by rishu6845
1

Answer:

432

Explanation:

Given--->

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eˣ = 243 and eʸ = 32

To find --->There is a mistake in question

-----------

I think its like this

e³ˣ ⁺ ⁴ʸ/ ⁵ =?

Solution---->Now

--------------

eˣ = 243

We factorize 243

eˣ = 3×3×3×3×3

eˣ =3⁵

Now

eʸ = 32

We factorize 32 now

=2×2×2×2×2

eʸ =2⁵

e³ˣ⁺⁴ʸ/⁵ = e³ˣ/⁵ + ⁴ʸ/⁵

We have a law of exponent aᵐ⁺ⁿ =aᵐ aⁿ

applying this law here

= e³ˣ/⁵ e⁴ʸ/⁵

We have another law of exponent

( aᵐ) ⁿ =aᵐⁿ

= (eˣ )³/⁵ ( eʸ )⁴/⁵

= ( 3⁵ )³/⁵ ( 2⁵ )⁴/⁵

= 3³ 2⁴

= ( 3 × 3 × 3 ) ( 2× 2 ×2 ×2)

= ( 27 ) (16)

= 432

Additional information---->

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1)aᵐ / aⁿ = aᵐ⁻ⁿ

2)a⁰ = 1

3)aᵐ bᵐ = (ab)ᵐ

Answered by poojithalrdn13
1

Answer:

432

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