Question

each diagonal of a square I'd 12cm long. find its area

Answer 1

Let the side be s
Then, by Pythagoras theorem

(Diagnol)² = s²+s²
(12)²=2s²
(12×12)÷2=s²
6×12=s²
72=s²
s²=Area of square
Therefore, Area=***72 cm²***

Answer 2

Answer:

=> Area of a square is 72$cm^2$.

Step-by-step explanation:

Given that:

Diagonal of a square = $12cm$

To find:

The area of square = ?

As we know that,

The area of square = $\frac{1}{2}\times (digonal)^2$

$=> \frac{1}{2}\times 12\times 12$

Divide 2 by 12 we get,

$=>1\times 6\times 12$

Simplifying it further,

=> 72$cm^2$

Hence, the area of a square is 72$cm^2$.