Question

Each edge of a cube is increased by 50%.Find the percentage increase in the surface area of the cube.please answer this fast!!

Answer 1

Answer: 125% is the percentage increase for your question.

Let original length be "a"

So, Original surface area(S1) = 6a * a

Now, Increase in the length = 50%

So, new length = a + ((50/100) *a )

= (3a)/2

So, new surface area (S2) = 6 * (3a/2) * (3a/2)

= (27a*a)/2

So, Increase in surface area = S2 - S1

=((27a*a)/2) - (6a*a)

= (15a*a)/2

So, Percentage of increase in Surface Area

= ((((15a*a)/2) / (6a*a)) * 100 ) %

= 125%