the difference between two selling prices of a table at the profit of 5% and 7% is Rs.8. Find (a) cost prise of the table ,(b) selling price of the table.
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Solution:-
let cost prise of table = x rupees
1st salling price = x+ x×(5%)
2nd salling price = [x +x7%]
according to quetion:'
(x+7x/100)- (x+ 5x/100 ) = 8
107x/100 - 105x/100 = 8
2x/100 = 8
2x= 800
x= 400
(a) cost price = 400
(b)1st s.p = 400+400×5% = 420
2nd s.p = 400+400×7% = 428
let cost prise of table = x rupees
1st salling price = x+ x×(5%)
2nd salling price = [x +x7%]
according to quetion:'
(x+7x/100)- (x+ 5x/100 ) = 8
107x/100 - 105x/100 = 8
2x/100 = 8
2x= 800
x= 400
(a) cost price = 400
(b)1st s.p = 400+400×5% = 420
2nd s.p = 400+400×7% = 428
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