each edge of a cube us increased by 50% . The percentage increase in the surface are of the cube is ? Ans = 125% ... give me full solution
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Answered by
2
new edge= 150% of a
= 1.5 a
new surface area= 6 (1.5a)^2
= 6 2.25 a.a
increase = 6 a.a( 2.25-1)
= 6 a.a 1.25
percentage increase = 6a.a 1.25×100/ 6a.a
= 125
= 1.5 a
new surface area= 6 (1.5a)^2
= 6 2.25 a.a
increase = 6 a.a( 2.25-1)
= 6 a.a 1.25
percentage increase = 6a.a 1.25×100/ 6a.a
= 125
Answered by
4
Let the edge of a cube be 'x'.
Given that each edge of a cube increased by 50%.
⇒ x + 50% of x
⇒ x + x/2
⇒ 3x/2.
We know that surface area of a cube = 6x^2
⇒ 6(3x/2)^2
⇒ 54/4 x^2
⇒ 13.5 x^2.
So, the increase in area = 13.5x^2 - 6x^2
⇒ 7.5x^2.
Now,
% increase in area = (Increased area/original area) * 100
⇒ (7.5/6) * 100
⇒ 125%.
Hope this helps!
suhana3321:
plz plz can you answer my previous question which i have posted before this question
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