Question

Each element of an array arr[20][50] requires 4 bytes of storage . base address of arr is 2000. the location of arr[10][10] when the array is stored as column major is

Answer 1

Answer:

2840

column major = B + W *[(M * (J - Lc) + (I - Lr))]

Answer 2

Given,

Element of an array arr [20][50]

Storage required = 4 bytes

Base address of arr = 2000

To find,

Location of arr [10][10] when the array is stored in column-major

Solution,

Column Major = B + W [(M(J - Lc) + (l - LR))]

Location = 2000 + 4 ((10 - 0) x 20 + (10 - 0))

              = 2840

Thus, the location is 2840.