Question

each equal side of a isoscesles triangle is 8cm and base is 9 cm find it area

Answer 1

a=8 cm, b=8 cm and=9cm
s=
$\\ \frac{a + b + c}{2}$
$\frac{8 + 8 + 9}{2} cm = \frac{25}{2} \: cm = 12.5 \: cm$

Area=
$\sqrt{s(s - a)(s - b)(s - c)}$
$\sqrt{12.5(12.5 - 8)(12.5 - 8)(12.5 - 9)} {cm}^{2} = \sqrt{12.5(4.5)(4.5)(3.5)} {cm}^{2}$
$\sqrt{885.9375 {cm}^{4} }= 29.765 {cm}^{2}$

Hope it helps...... :-)
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