Each interior angle of a regular polygon is 144 degree. Find the interior angle of a regular polygon which has double the number of sides as the first polygon
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THE ANSWER IS 162⁰.
MEASURE OF EACH INTERIOR ANGLE
=> (n-2)180/n
144⁰ = (n-2)180/n
=> 144n=180n-360
=> After Transposing, -360 to the left side we are remain with
=>360=180n-144n
=>360=36n
∴ n = 360/36
=> 10
∵ THE FIGURE IS 10 SIDED REGULAR POLYGON (DECAGON).
ATQ , WE HAVE TO DOUBLE THE NO. OF SIDES = 10*2 = 20 SIDES.
ATQ , WE HAVE TO FIND THE MEASURE OF THE INTERIOR ANGLE IN THAT 20 SIDED POLYGON.
MEASURE OF EACH INTERIOR ANGLE =
(n-2)180/n Here, n( no. of sides ) = 20
ATQ , (20-2)180/20
= 18*180/20
= 162⁰
PLZ MARK ME THE BRAINLIEST.
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@harshdynamo
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3
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162
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