Question

each interior angle of a regular polygon is 160°.find the interior angle of regular polygon which has double the number of sides as the given polygon

Answer 1

Given:

Each interior angle of a regular polygon = 160°

To find:

The interior angle of regular polygon which has double the number of sides as the given polygon.

Solution:

The interior angle of a polygon with n sides = 180(n-2) / n

Here 160 = 180(n-2)/ n

160n = 180n - 360

180n - 160n = 360

20n = 360

n = 18

If a polygon has double the number of sides as the given polygon then n= 18*2 = 36

Each interior angle = 180(n-2) / n

= 180(36-2) / 32

= 180*34 / 36

= 5* 34

= 170°

Therefore the interior angle of the required polygon is 170°.

Answer 2

Answer:

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