Question

each interior angle of regular polygon is 144 degree find the interior angle of a regular polygon which has double the number of sides in the first polygon​

Answer 1

Given: interior angle of regular polygon= 144 °

interior angle of a regular polygon =

${(n - 2) \times 180 degree} \div n \\ 144 \: degree \: = (180n - 360) \div n \\ 144n \: = \: 180n - 360 \\ 180n - 144n \: = 360 \\ n \: = 10$

So, there are 10 sides in 1st given example.

So,We have find interior angle of regular polygon of 20 sides.

You can find it with the formula = {(n-2)×180}°÷n

where n is number of sides of regular polygon.

Hope it helps you!

Answer 2

Answer:

》》Interior angle = 144°

》》Exterior angle=180°-144°=36°

☆Number of sides=360°/36°=10 sides