Question

Each of equal sides of an isosceles triangle is 4 cm greater than its height.
If the length of base of a triangle is 24 cm. Calculate the perimeter and
the area of isosceles triangle.
accions.​

Answer 1

Answer:

Perimeter = 64cm

Perimeter = 64cmArea = 192cm²

Step-by-step explanation:

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Answer 2

Answer:

Area = 192 sq.cm

Perimeter = 64cm

Step-by-step explanation:

Let height = x cm then,

2 equal sides = (x+4) cm

in triangle ABD and ACD

AD=AD

AB=AC

Angle ADB=Angle ADC=90

by RHS congruency Triangle ABD is congruent to triangle ACD

by CPCT, BD=CD=12 cm

Applying Pythagoras theorem,

(x+4)^2 = (x)^2 + (12)^2

x^2 + 8x + 16 = x^2 =144

8x=128

x=16

equal side = x+4= 20 cm

height=16 cm

area = 1/2 x b x h

        = 1/2 x 24 x 16

=192 cm^2

Perimeter= 20cm +20cm+24cm

= 64 cm