Question

Each of equal sides of isosceles right triangle is 20 cm. what is the semi perimeter of the triangle​

Answer 1

Answer: 20 + 10 root 2

Step-by-step explanation:

Let ABC be an isosceles right triangle in which

2 cm

AB =AC =20cm

Hypotenuse BC = AB2+AC2 = a2+a2

=a 2=20 2cm. s =20+20+20 root 2

=40+20root  2 =20+10 root 2

Answer 2

Answer:

$20 + 10\sqrt{2}$

Step-by-step explanation:

The triangle is iscoleces.

Each equal side measures 20 cm.

Now, when the iscoleces triangle is a right-angled triangle, it happens to be that the equal sides are perpendicular to each other.

Using Pythagoras Theorem,

-> $20 + 10\sqrt{2}$

-> $Hypotenuse = \sqrt{ (equal side^{2}) + (Equal side^{2}) }$

-> $Hypotenuse = \sqrt{(20^{2}) + (20^{2})}$

-> $Hypotenuse = \sqrt{(400) + (400)}$

-> $Hypotenuse = \sqrt{800}$

-> $Hypotenuse = 20\sqrt{2}$

Semi-perimeter:-

=> $\frac{Perimeter}{2}$

=> $\frac{20 + 20 + 20\sqrt{2}}{2}$

=> $\frac{40 + 20\sqrt{2}}{2}$

=> $20 + 10\sqrt{2}$

Thus, the answer is $20 + 10\sqrt{2}$