Question

Each of height and side of the base of a regular hexagonal pyramid is equal to x cm . Find its.
lateral surface area in terms of x

Answer 1

Answer:

Since, the lateral surface area of a hexagonal pyramid,

$A_L = 3a\sqrt{h^2+\frac{3a^2}{4} }$

Where a be the side of the hexagon,

And, h be the height of the pyramid,

Here, a = x unit  and h = x unit,

Therefore,

$A_L = 3x\sqrt{x^2+\frac{3x^2}{4} }$

$A_L = 3x\sqrt{x^2(1+\frac{3}{4}) }$

$A_L = 3x^2\sqrt{(1+\frac{3}{4}) }$

$A_L = 3x^2\sqrt{(\frac{7}{4}) }$

$A_L = \frac{3x^2\sqrt{7}}{2}\text{ square unit}$

Answer 2

Answer:

Refer to the above one.