Question

Each of the two equal angles of a triangle is twice the third angle.Find the angles of the triangle.
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Answer 1

Step-by-step explanation:

let the third angle of the triangle be x

therefore,

Angle 3=x

Since, Angle 1 and 2 are twice the third angle....

Therefore,

Angle 1=Angle2=2x

Angle 1 + Angle 2 + Angle 3 = 180 °

(Angle Sum Property of a triangle)

2x + 2x+ x= 180°

5x=180°

x=36°

Therefore,

Angle 1 = Angle 2= 2x = 2*36°=72°

Angle 3= x = 36°

Therefore all the angles are 72° ,72° ,36°

Answer 2

Step-by-step explanation:

(1step) -let the third side of the triangle be "x".

(2step)-each of the two equal angles of the triangle are 2x and 2x respectively.

(3 step)- therefore the equation is :- 2x+2x+x is equal to 180.

(as the sum of all the sides of a triangle is 180 degrees).

(4step)- therefore 5x equal to 180 degrees.

(5 step)- therefore X equal to 180 divided by 5 which is equal to 36.

(6step)-therefore all the angles of the triangle are: -

first angle:- 2x that is 36 into 2 which is 72.

second angle:- 2x that is 36 into 2 which is 72.

third angle:- x that is 36.