each of the two equal angles of an isosceles triangle is twice the third angle find the angles of the triangle
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Answered by
10
Heya mate,Here is ur answer
Let the third angle be x.
A/Q
Equal angles =2x
By Sum angle property of a ∆
angle A+Angle B+Angle C=180°
x+2x+2x=180°
5x=180°
x=36
So angle A=36°
Angle B=2×36
=72°
Angle C=2×36
=72°
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@Laughterqueen
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Let the third angle be x.
A/Q
Equal angles =2x
By Sum angle property of a ∆
angle A+Angle B+Angle C=180°
x+2x+2x=180°
5x=180°
x=36
So angle A=36°
Angle B=2×36
=72°
Angle C=2×36
=72°
Warm regards
@Laughterqueen
◦•●◉✿[Tʜᴀɴᴋ ʏᴏᴜ]✿◉●•◦
●▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬●
Be Brainly ✌✌✌
Rajivranjanroy:
thanks
Answered by
5
let 3rd angle be x
the the two equal angles will be both 2x
now,
we know that
2x + 2x + x = 180
5x =180
x. =180/5
x. =36
1st angle = 2x =2×36 = 72
2nd angle = 2x = 2×36 = 72
3rd angle = x = 36
the the two equal angles will be both 2x
now,
we know that
2x + 2x + x = 180
5x =180
x. =180/5
x. =36
1st angle = 2x =2×36 = 72
2nd angle = 2x = 2×36 = 72
3rd angle = x = 36
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