Each of the two point charges are doubled and thier distance is halved force of interaction becomes n times where
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Answer:
the value of n will be 16.
Explanation:
By Coulomb's law, the force between two charges q
1
and q
2
is F=
r
2
kq
1
q
2
where r= separation between charges.
When charges are doubled and their distance is halved , the force of interaction becomes F
′
=
(r/2)
2
k(2q
1
)(2q
2
)
=16F
Thus, the value of n will be 16.
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