Math, asked by tejvirsinghu7584, 2 months ago

Set of equations a+b-2c=0, 2a-3b+c=0 and a-5b+4c=alpha is consistent for alpha equals to (A) 1 (B) 0 (C) -1 (D) 2

Answers

Answered by pulakmath007
3

SOLUTION

TO CHOOSE THE CORRECT OPTION

Set of equations a + b - 2c = 0, 2a - 3b + c = 0 and a - 5b + 4c = α is consistent for α equals to

(A) 1

(B) 0

(C) - 1

(D) 2

EVALUATION

Let the given Set of equations

a + b - 2c = 0, 2a - 3b + c = 0 and a - 5b + 4c = α

are consistent

 \sf{ \therefore  \:  \:  \Delta_x = 0}

\displaystyle \implies \: \begin{vmatrix}  1 &  - 2 & 0\\  - 3 & 1 &  0 \\  - 5 & 4 &   \alpha  \end{vmatrix} = 0

\displaystyle  \sf{\implies \:1( \alpha  - 0) - 2( - 3 \alpha  - 0) + 0 = 0}

\displaystyle  \sf{\implies \:7 \alpha   = 0}

\displaystyle  \sf{\implies \: \alpha   = 0}

FINAL ANSWER

Hence the correct option is (B) 0

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