Physics, asked by dhairyatewatia9218, 10 months ago

Each of the two strings of length 51.6 cm and
49.1 cm are tensioned separately by 20 N force.
Mass per unit length of both the strings is same
and equal to 1 g/m. When both the strings
vibrate simultaneously the number of beats
is
(a) 7 (b) 8 (c) 3 (d) 5

Answers

Answered by Anonymous
0

Answer :- Option C......

Answered by AishG
0

Explanation:

Each of the two strings of length 51.6 cm and

49.1 cm are tensioned separately by 20 N force.

Mass per unit length of both the strings is same

and equal to 1 g/m. When both the strings

vibrate simultaneously the number of beats

is

(a) 7 (b) 8 (c) 3 (d) 5

Option C

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