Question

Each of three bulb having same resistance can dissipate maximum power P0 The maximum power the circuit of three bulbs can dissipate is​

Answer 1

Answer:

Each board has three 40-watt bulbs, connected as shown by the resistor circuit painted on it. ... When the bulbs are connected in parallel, each bulb has 120 V across it, ... In this circuit, all bulbs glow at their full brightness. ... this, we can at least roughly estimate the current flow and power dissipation in the series circuit.

Explanation:

Answer 2

Concept:

In physics, power is the amount of energy that is transferred or transformed in a given amount of time. Since the resistance is the same, thus the maximum power of the circuit will be the sum of each bulb's power.

Given:

The resistance of the three bulbs was the same = R

Maximum power dissipated by each bulb = P

Find:

We need to determine the maximum power the circuit of three bulbs can dissipate.

Solution:

• In physics, power is the amount of energy that is transferred or transformed in a given amount of time

• The International System of Units uses the watt, or one joule per second, as the unit of power.
• According to the problem, in order to determine the Maximum Power, we just sum the powers of the three bulbs because they all have the same resistance and, as a result, have the same power, P.
• Consequently, the circuit's maximum power is, Pmax = P + P + P
• Pmax = 3P

Therefore, the maximum power the circuit of three bulbs can dissipate is 3P.

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