Each of two equal sides of a triangle is 3 cm less than the twice the third side. If the perimeter of the triangle is 69 cm find the length of its side
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Let the third angle be x
Then, first angle = second angle= 2x - 3 Perimeter= 69cm
A.T.Q.
(2x -3 ) + (2x - 3 ) + x = 69
OR2x - 3 + 2x - 3 + x = 69
OR 2x + 2x + x = 69+3+3
OR 5x = 69+6
OR5x = 75
OR x = 15
Therefore,
first angle=second angle = 2x - 3 =30 - 3= 27 cm
third angle= 15 cm
Then, first angle = second angle= 2x - 3 Perimeter= 69cm
A.T.Q.
(2x -3 ) + (2x - 3 ) + x = 69
OR2x - 3 + 2x - 3 + x = 69
OR 2x + 2x + x = 69+3+3
OR 5x = 69+6
OR5x = 75
OR x = 15
Therefore,
first angle=second angle = 2x - 3 =30 - 3= 27 cm
third angle= 15 cm
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