Each side of a cube is measured to be 7.203 m. What is (i) the total surface area and (ii) the volume of the cube to appropriate significant figures.
Answers
Answered by
2
Hello
the answer is
T.S.A = 6a^2
= 6×7.203^2
= 6×51.883209
= 311.299254
volume of cube = (a)^3
= (7.203)^3
= 373.714654427
Hope, it will help you...
MARK ME AS BRAINLIST
the answer is
T.S.A = 6a^2
= 6×7.203^2
= 6×51.883209
= 311.299254
volume of cube = (a)^3
= (7.203)^3
= 373.714654427
Hope, it will help you...
MARK ME AS BRAINLIST
Answered by
0
Hii dear,
# Answer-
A = 311.3 sq.m
V = 373.7 cu.m
# Solution-
Consider l be the side of cube.
Given is
l = 7.203 m (4 significant figures)
Area and volume of the cube should be upto least significant figures.
i.e. here 4.
Surface area of cube-
A = 6l^2
A = 6×(7.203)^2
A = 311.299254
A = 311.3 sq.m (4 significant figures)
Volume of cube-
V = l^3
V = (7.203)^3
V = 373.714754427
V = 373.7 cu.m (4 significant figures)
That'll help you...
# Answer-
A = 311.3 sq.m
V = 373.7 cu.m
# Solution-
Consider l be the side of cube.
Given is
l = 7.203 m (4 significant figures)
Area and volume of the cube should be upto least significant figures.
i.e. here 4.
Surface area of cube-
A = 6l^2
A = 6×(7.203)^2
A = 311.299254
A = 311.3 sq.m (4 significant figures)
Volume of cube-
V = l^3
V = (7.203)^3
V = 373.714754427
V = 373.7 cu.m (4 significant figures)
That'll help you...
Similar questions