Question

Each side of a cube to be 50 percent increase what will be growth in the surface area of the cube

Answer 1

Answer:

let each side of the cube be = x

let surface area if the cube = 6x²

so... increased %of the side is = 50%

now.. new side will be = x+(50/100*x)

x+x/2

$\frac{3x}{2}$

now.. new surface area will be =

$6 \times \frac{3x}{2} \times \frac{3x}{2}$

$3 \times 3x \times \frac{3x}{2}$

$\frac{27x {}^{2} }{2}$

increase in surface area = new surface area-old surface area

=

$\frac{27x {}^{2} }{2} - 6x {}^{2}$

$\frac{15x {}^{2} }{2}$

increased % = 15x²/2/6x²*100

15/2/3*50

5/2*50

5*25

125%

thank you

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