Each side of a given polygon is parallel to either the X or the Y axis. A corner of such a
polygon is said to be convex if the internal angle is 90° or concave if the internal angle is
270°. If the number of convex corners in such a polygon is 25, the number of concave
corners must be
A..21
B.22
C.23
D.24
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Given :-
- Each side of a given polygon is parallel to either the X or the Y axis.
- A corner of such a polygon is said to be convex if the internal angle is 90° or concave if the internal angle is 270°.
- The number of convex corners in such a polygon is 25.
To Find :-
The number of concave corners must be :-
A..21
B.22
C.23
D.24
Solution :-
Let us assume that, the total number of 90° angle is x and the total number of 270° angle is y.
Than,
→ sum of all 90° angles = 90 * x = 90x
→ sum of all 270° angles = 270 * y = 270y .
and,
→ Total sides polygon = (x + y).
Now, we know that,
- sum of all interior angles of a polygon with n sides is equal to = (n - 2) * 180° .
So,
→ sum of all angles of polygon with total sides (x + y) = [x + y - 2] * 180° .
Therefore,
→ 90x + 270y = (x + y - 2) * 180°
→ 90x + 270y = 180x + 180y - 360°
→ 180x - 90x + 180y - 270y = 360°
→ 90x - 90y = 360°
→ 90(x - y) = 360°
dividing both sides by 90°
→ x - y = 4
Putting given value of x = 25 now,
→ 25 - y = 4
→ y = 25 - 4
→ y = 21. (Option A) (Ans.)
Hence, the number of concave corners must be 21.
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